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 The PLAN Procedure

## Example 50.2: A Hierarchical Design

In this example, three plants are nested within four pots, which are nested within three houses. The FACTORS statement requests a random permutation of the numbers 1, 2, and 3 to choose Houses randomly. The second step requests a random permutation of the numbers 1, 2, 3, and 4 for each of those first three numbers to randomly assign Pots to Houses. Finally, the FACTORS statement requests a random permutation of 1, 2, and 3 for each of the twelve integers in the second set of permutations. This last step randomly assigns Plants to Pots. The following statements produce Output 50.2.1:

```   title 'Hierarchical Design';
proc plan seed=17431;
factors Houses=3 Pots=4 Plants=3 / noprint;
output out=nested;
run;

proc print data=nested;
run;
```

Output 50.2.1: A Hierarchical Design

 Hierarchical Design

 Obs Houses Pots Plants 1 1 3 2 2 1 3 3 3 1 3 1 4 1 1 3 5 1 1 1 6 1 1 2 7 1 2 2 8 1 2 3 9 1 2 1 10 1 4 3 11 1 4 2 12 1 4 1 13 2 4 1 14 2 4 3 15 2 4 2 16 2 2 2 17 2 2 1 18 2 2 3 19 2 3 2 20 2 3 3 21 2 3 1 22 2 1 2 23 2 1 3 24 2 1 1 25 3 4 1 26 3 4 3 27 3 4 2 28 3 1 3 29 3 1 2 30 3 1 1 31 3 2 1 32 3 2 2 33 3 2 3 34 3 3 3 35 3 3 2 36 3 3 1

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